if ( n+ 2) ! = 60 [ ( n-1 ) ! ] find n .....plzzzzzz answer fast
Anomi:
(n+2)(n+1)(n)(n-1)! = 60(n-1)! cancelling (n-1)! from both sides we get.. n(n+1)(n+2) =60 so. n=3
Is it right?
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n+2 = 60(n-1)
n+2=60n-60
2+60 = 60n-n
62 = 59 n
n= 62/59
n+2=60n-60
2+60 = 60n-n
62 = 59 n
n= 62/59
what u had done ....??? its factorial
you may divide it and get answer in points
its factorial not a simple equation
3 will be answeer
(n+2)(n+1)(n)(n-1)! = 60(n-1)! cancelling (n-1)! botj sides. w get n =3
hey aanya its ankit here.. i was unable to send u texts.. it was showing some error..
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