Question

if (n+2)!/(n+1)!-10!/9!=6,value of n

Answer 1

hello... here is your answer.................

Answer 2

Given Equation is:

$\frac{(n + 2)!}{(n + 1)!} - \frac{10!}{9!} = 6$

$\frac{(n + 2)(n + 1)}{(n + 1)} - \frac{10*9*8*7*6*5*4*3*2*1}{9*8*7*6*5*4*3*2*1} = 6$

[tex]n + 2 - 10 = 6 [/tex]

n - 8 = 6

n = 6 + 8

n = 14.


Hope this helps!