Question

if n-2,n,n+2,n+4 is in ap then s10​

Answer 1

Answer:

a=n-2

d=n-n+2

 =2

n=10

S10=n/2[2a+(n-1)d]

S10=5[2n-4+18]

S10=5[2n+14]

S10=10n+70

Answer 2

Hope this helps this is the required answer