If n = (2 x 10squared) + 3, then find the sum of the digits of n squared
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As the last digit of n^2 is 4 , then last digit of n is either 2 or 8 .
If we consider the last digit as 2 , then the digit before 4 can't be a odd number (as 5). It must be a even number ( it is a sum of the two same numbers, you can check this by taking any three digit ending with 2)
If we consider that last digit is 8 , then also the digit before 4 is a even number , as it is sun the of two same numbers + 6 .
So there is no value for n .
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