If N = (243 + 253 + 263 + 273), then N divided by 102 leaves a remainder of?
18
12
1
0
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0
Answer:
Choice D is the correct answer.
Step-by-step explanation:
Unit digits of N = 4 + 5 + 6 + 3 = 18
N is divisible by 2
We know that, a3 + b3 = (a + b)(a2 – ab + b2)
=> (a + b) always divides a3 + b3
Therefore, 243 + 273 is divisible by 51 (24 + 27)
Also, 253 + 263 is divisible by 51 (25 + 26)
The given divisor 102 can be expressed as 51 * 2
Hence, N is completely divisible by 102
Remainder = 0
The question is "If N = (243 + 253 + 263 + 273), then N divided by 102 leaves a remainder of?"
Hence the answer is 0.
Choice D is the correct answer.
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