Math, asked by bst938, 10 months ago

if N=28^99-27^99/28^98+27^98 then value of
a. N<1
b.N<0
c.N>9
d.N>1​

Answers

Answered by Anonymous
7

N =  \frac{ {28}^{99}  -  {27}^{99} }{ {28}^{98}  +  {27}^{98}  }

N =  \frac{1.8562869e143 - 5.0700548e141}{6.6295961e141 + 1.8777981e140}

N =  \frac{1.8055864e143 }{6.8173759e141}

{N = 26.4850644366}

Hence, d. N>1

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