if n= 2to the power3 *3to the power4*7*15power to the 6, find the number of consecutive zeroes in natural number n?
Answers
Answered by
4
hi
n = 2³ * 3⁴ * 7 * 15⁶
= 2³ * 3⁴ * 7 * 3⁶ * 5⁶
we get 0, when we multiply a 2 with a 5.
So there are three 2s, six 5s and hence we get 3 consecutive zeros in the value of n.
thank u
n = 2³ * 3⁴ * 7 * 15⁶
= 2³ * 3⁴ * 7 * 3⁶ * 5⁶
we get 0, when we multiply a 2 with a 5.
So there are three 2s, six 5s and hence we get 3 consecutive zeros in the value of n.
thank u
hza1:
explain in detail plz
Answered by
0
fhhjxhx,fu xcjxizixixkdiyzizyxiyuod
Similar questions
Physics,
8 months ago
Computer Science,
8 months ago
Physics,
1 year ago
CBSE BOARD X,
1 year ago
Math,
1 year ago