if n= 2to the power3 *3to the power4*7*15power to the 6, find the number of consecutive zeroes in natural number n?
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hi
n = 2³ * 3⁴ * 7 * 15⁶
= 2³ * 3⁴ * 7 * 3⁶ * 5⁶
we get 0, when we multiply a 2 with a 5.
So there are three 2s, six 5s and hence we get 3 consecutive zeros in the value of n.
thank u
n = 2³ * 3⁴ * 7 * 15⁶
= 2³ * 3⁴ * 7 * 3⁶ * 5⁶
we get 0, when we multiply a 2 with a 5.
So there are three 2s, six 5s and hence we get 3 consecutive zeros in the value of n.
thank u
hza1:
explain in detail plz
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