if n^3+3n^2+2n is the product of the numbers in a pythagoren triplet then find the triplet
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Answer:
Step-by-step explanation:
n^3 + 3n^2 + 2n = n(n + 1 )(n + 2)
n = 3 , n + 1 = 4 , n + 2 = 5
hasinisekhar:
how can ypu get n=3...explain step by step
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