Question

if N= ³√4+³√2+1, then find 1/N³+3/N²+3/N?​

Answer 1

Answer:

Hint : 1(1!) + 2(2!) + 3(3!) + ... + n(n!) + (n+1) (n+1)! = (n +1)! - 1 + (n+1)(n+1)! = ? ... Then for n + 1 cents postage case, if (n + 1) - 5 = n - 4 ³ 24 ,

Answer 2

Answer:

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