Question

If(n+3)!=56×(n+1)! ,Then find n.

Answer 1

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Here is your answer...✌
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(n+3)! = 56×(n+1)!

=> (n+3)×(n+2)×(n+1)! = 56×(n+1)!

=> (n+3)×(n+2) = 56

=> (n+3)×(n+2) = 8×7

By comparing ,

=> n+3 = 8

=> n = 8-3

=> n = 5

Answer 2

$\large \underline{\underline{ \bold{ \: Answer : \: \: \: }}}$

$\to$ n = 5

$\large \underline{\underline{ \bold{ \: Explanation : \: \: \: }}}$

$\to$ (n + 3)! = 56(n + 1)!

$\to$ (n + 3)(n + 2)(n + 1)! = 56(n + 1)!

$\to$ (n + 3) (n + 2) = 56

$\to$ (n + 3) (n + 2)= 8 × 7

By comparing

$\to$ n + 3 = 8

$\to$ n = 8 - 3

$\to$ n = 5