if n= 3 q + 2 then check whether n+ 7 is divisible by 3 for some integer q.
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n = 3q+2
n+7 = 3q+2 +7
= 3q +9
by taking out the common factor,
n +7 = 3 ( q+3)
so n+7 is a multiple of 3, for all n.
therefore, n+7 is divisible by 3 for all n
n+7 = 3q+2 +7
= 3q +9
by taking out the common factor,
n +7 = 3 ( q+3)
so n+7 is a multiple of 3, for all n.
therefore, n+7 is divisible by 3 for all n
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