Question

If n(ξ) = 40, n(A) = 20, n(B’) = 16 and n(A ∪ B) = 32, then find n(B) and n(A ∩ B)​

Answer 1

Answer:

ans:

given that: n(A) =20

n(B) =16

n(A u B) =32

n(Aub) =n(A) +n(B) -n(AnB)

32=20+16-n(AnB)

-n(AnB) =32-36

n(AnB) =4