Question

If n=40, S.D=2.06 then the maximum
error with 99% confidence is
Select one or more:
O A. 0.536
OB. 0.8387
C. 0.7377
O D. 0.6387​

Answer 1

Answer:

If n=40, S.D=2.06 then the maximum error with 99% ... Select one or more: O A. 0.536. OB. 0.8387. C. 0.7377. O D.

Answer 2

The maximum error with 99% confidence is 0.8387

Therefore, option (B) is correct.

Explanation:

Given

No. of samples $n = 40$

Standard Deviation $\sigma=2.06$

We know that z* for 99% confidence is 2.575

The maximum error is given by

$E=z*\frac{\sigma}{\sqrt{n}}$

$\implies E=2.575\times\frac{2.06}{\sqrt{40}}$

$\implies E=2.575\times\frac{2.06}{6.3246}$

$\implies E=0.8387$

Therefore, option (B) is correct

Hope this answer is helpful.

Know More:

Q: Which three inputs are required to calculate a confidence interval at a given level of confidence?

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