Question

If N = √√5+2+√√5-2/√√5+1-√3-2√2, then N equals

Answer 1

x=5+2√6x=5+26

=> x=2+3+2√2√3x=2+3+223

=> x=(√2)2+(√3)2+2√2√3x=(2)2+(3)2+223

=> x=(√2+√3)2x=(2+3)2

=> √x=√2+√3x=2+3

x−1=5+2√6−1=4+2√6=2√2(√2+√3)x−1=5+26−1=4+26=22(2+3)

∴x−1√x=2√2(√2+√3)√2+√3∴x−1x=22(2+3)2+3

=> x−1√x=2√2

Answer 2

Step-by-step explanation:

we can write √(3-2√2) as√2-1

#add √2-1 to both side

#square both the sides

#then in rhs take 2 common in numerator due to which (√5+1) gets cancel out

#square root both sides and cancel out √2

#here we go ,we get N=1