Question

If n(ξ) = 50, n(A) = 15, n(B) = 13 and n(A ∩ B) = 10. Find n(A’), n(B’) and n(A ∪ B). ​

Answer 1

Answer:

n (A U B) = n(a) + n (b) -(A intersect B)

= 28 - 10

= 18.

n(A') =n(u) - n (A)

= 50- 15

= 35.

n(B') = n(u) - n(B)

= 50 - 13

= 37.

hope it helps.

Answer 2

Answer:

n(A')= 35, n(B')= 37, n( A u B)= 18

Step-by-step explanation:

Given:

n(ξ) = 50

n(A)= 15

n(B)= 13

n(A ∩ B) = 10

To find: n(A’), n(B’) and n(A ∪ B)

A set is a grouping of unique components and members.

We shall make 2 different equations for this solve:

Equation 1

- n(ξ)- n(A)= n(A')

- 50-15= 35

Hence n(A')= 35

Now that we have n(A') Similarly we shall find n(B')

- n(ξ)- n(B)= n(B')

- 50-13= 37

Hence n(B')= 37

Equation 2

- n(A u B)= n(A)+ n(B)- n(A ∩ B)

- n(A u B)= 15+13-10

- n(A u B)= 18

Hence n(A u B)= 18

This is our answer

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