Question

if n=6,m=5,l=8, find the value of n^2-m^2+l^2/
3n+6l^2-4mn
iska answer 25/94 hona chahiye
solution bta do​

Answer 1

Answer:

732

Step-by-step explanation:

n²+m²+12

=(6)²×(5/8)²+12

=36×25/64+12

=18×25/32+12

=9×25/16+12

=144×25+12

_____

| =3612 |

| |

___

Answer 2

Answer:

here is answer - 25/94

Step-by-step explanation:

n=6 m=5 l=8

To find :

$\frac{ {n}^{2} - {m}^{2} + {l}^{2} }{3n + 6 {l}^{2} - 4mn}$

$\frac{{6}^{2} - {5}^{2} + {8}^{2} }{3(6) + 6 {(8)}^{2} - 4(5)(6) }$

= 36 - 25 + 64 / 18 + 6*64 - 120

= 11+64 / 18 + 384 - 120

= 75 / 264 + 18

= 75 / 282

(divide numerator and denominator by 3)

=25 / 94