Question

If n! =6(n-2)! Then find n
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Answer 1

SOLUTION

GIVEN

$\sf{n! = 6(n - 2)!}$

TO DETERMINE

The value of n

EVALUATION

$\sf{n! = 6(n - 2)!}$

$\sf{ \implies \: n(n - 1) \times (n - 2)! = 6 \times (n - 2)!}$

$\sf{ \implies \: n(n - 1) = 6 }$

$\sf{ \implies \: n(n - 1) = 3 \times 2 }$

Comparing both sides we get n = 3

FINAL ANSWER

Hence the required value of n = 3

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