If n=6, the correct sequence for filling of electrons will be :
Options:
ns→np (n−1)d→(n−2)f
ns→(n−2)f→(n−1)d→np
ns→(n−1)d→(n−2)f→np
ns→(n−2)f→np(n−1)d
Answers
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Option b is the correct answer.
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