Chemistry, asked by deepak1869, 1 year ago

If n=6, the correct sequence for filling of electrons will be :









Options:














ns→np (n−1)d→(n−2)f







ns→(n−2)f→(n−1)d→np







ns→(n−1)d→(n−2)f→np







ns→(n−2)f→np(n−1)d

Answers

Answered by rakeshmohata
6
Option b is the correct answer.
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