Question

If n = 67 then find the unit digit of [3ⁿ+2ⁿ]​

Answer 1

Step-by-step explanation:

n=67

∴

4

n−1

=

4

67−1

=

4

66

=16

4

2

∴remainder=4

∴Requiredlastdigit=unitdigitin(3

3+1

)+unitdigitof(2

3+1

)

=Unitdigitin27+Unitdigitin8

=unitdigitin(7+8)

=unitdigitin(15)=5