Question

If n = 67 then find the unit digit of [3n

+ 2n

].

(A) 1 (B) 10 (C) 5 (D) None

Answer 1

hey dear here is your answer ⬇️⬇️☺️

if 'n' =67 then the value of (3n+2n) is
=(3×67+2×67)
=(201+134)
=335

hope it helps you ✌️

Answer 2

Hey there,

A little correction in ur question

n=67, unit digit of 3^n+2^n

=>3^67+2^67=3^(4k+3) + 2^(4k+3) ,where k=16.

By cyclicity of 3and 2,unit digit of 3^(4k+3)=7 and 2^(4k+3)=8.
So,Sim's unit digit=8+7=..5

So, unit digit=C)5.

Hope it helps and Mark it as branliest