if n=8 nd p=1/2 nd q=1/2 then find the binomial distribution in case of when atleast 2 success
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Answered by
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Answer:
Let n and p be the parameters of binomial distribution.
Given, mean = np=4
Variance = npq=2
Thus,
np
npq
=q=
2
1
p=
2
1
n=8
Hence, binomial distribution is given by :
=P(X=5)+P(X=6)+P(X=7)+P(X=8)
=8
C
5
(
2
1
)
5
(
2
1
)
3
+8
C
6
(
2
1
)
6
(
2
1
)
2
+8
C
7
(
2
1
)
7
(
2
1
)+8
C
8
(
2
1
)
8
=
256
93
I Hope This Answer Helped You
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