if n(a) =0find n[p(a)]
if n [p(a)]=256findn(a)
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Explanation:
(i) n( A) = 4 n[ P(A)] = 2n = 24 = 16 (ii) n(A) = 0 n[P(A)] = 20 = 1 (iii) n[P(A)] = 256 n[P(A)] = 28 ∴ n(A) = 8.i-if-n-a-4-find-n-p-a-ii-if-n-a-0-find-n-p-a-iii-if-n-p-a-256-find-n-a
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