if n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is
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130 is the answer
Step-by-step explanation:
n(A)=100,n(B)=70 and n(A∩B) = 20
n(A∪B) = n(A) + n(B) - n(A∩B)
n(A∪B) = 100 + 70 - 20
=170 -20
= 150
n(AΔB) = n(A∪ B) - n(A∩B)
= 150 - 20
= 130
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