If n(A) = 12 , n( A∩B) = 10 and n( AUB) = 40 then n(B) *
(i) 25
(ii) 20
(iii) 38
(iv) 18
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Step-by-step explanation:
n(A intersectionB) 12+10=-2
n(A union B) -2+40=38
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