Math, asked by huzziyume, 5 hours ago

If n(A) = 12 , n( A∩B) = 10 and n( AUB) = 40 then n(B) *
(i) 25
(ii) 20
(iii) 38
(iv) 18

Answers

Answered by sagarmanav60

1

Step-by-step explanation:

n(A intersectionB) 12+10=-2

n(A union B) -2+40=38

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