If n ( A ) = 12 , n ( B ) = 15 and n(A∩ B) = 3 then n(A ∪ B )
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n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)=7
n(B)=9
n(A∪B)=14
Substituting in 1
14=7+9−n(A∩B)
⇒n(A∩B)=16−14=2
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