Question

If n(A)=12, n(B)=16, n(C)=21, n(A∩B)=5 ,n(A∩C)=8 ,n(B∩C)=12, n(A∩B∩C)= 12 then n (A U B U C ) = *

Answer 1

Answer:

36

Explanation:

n(A∪B∪C)=n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(A∩C) + n(A∩B∩C)

               =12+16+21-5-8-12+12

               =36