If n(A)=12, n(B)=8, n(A∪B)=14 then n(A∩B)=?
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Hence sum of no. of elements in A(n(A)) and no. of elements in B (n(B)) can be given as
n(A)+n(B)=n(AuB)+n(AnB)
Thus to find n(AnB)
n(AnB)=n(A)+n(B)-n(AuB)
=7+5-11
=12
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