Question

If n(A) = 120, n(B) = 25, n (A-B)=52 i
find n(AUB)​

Answer 1

Answer:

• n(A-B)=n(A)-n(A^B)=52
• by substituting value
• we get n(A^B)=68
• n(A)+n(B)-n(A^B)=n(AUB)
• by substituting values we get
• n(AUB)=77