Question

if n(A)=130,n(B)=180,n(A intersection B)=110.find n(AUB)

Answer 1

n(AUB) = 130+180-110 = 200

Answer 2

Answer:

The value of n(A∪B) is 200.

Step-by-step explanation:

Since, we know that,

$n(A\cup B) = n(A) + n(B) - n(A\cap B)$,

We have given,

n(A) = 130, n(B) = 180 and n(A∩B) = 110,

Thus,

$n(A\cup B) = 130 + 180 - 110$

$= 310 - 110$

$= 200$

Hence, the value of n(A∪B) is 200.