If n(A)=130, n (B)=180,n(A intrsection B)=110 , find n (A union B).give the solution
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hey there
your answer is
(AUB)= n(A) + n(B) - n(AnB)
(AUB)=130+180-110
=210-110
= 100
therefore (AUB) =100
hope this helps you!!
aatiffff:
wrong answer
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