If n (A)=15,n (A-B)=10 , then find n (AUB) ?
Answers
Answered by
3
Answer:n(B)+ 10
Step-by-step explanation:n(A)= 15
n(A-B)=10
Thus, n(AUB)=n(A)+n(B)-n(AintersectionB)
= 15+n(B) -n(A intersection B)
=15 +n(B)-5
=10+ n(B)
We need to know the value of n(B).
Answered by
0
Step-by-step explanation:
n(AUB)=n(a)+n(b)-n(A intersection B)
n(AUB)1=10+n(b)
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