Math, asked by guggu24, 11 months ago

If n(A)=15, n(AUB)=29, n(AnB)=7, then n(B)=?​

Answers

Answered by rajsingh24
2

Answer:

hey mate your answer is...

Step-by-step explanation:

n(aub) = n(a) - n(b) + n(anb) \\ 29 = 15 - n(b) + 7 \\ n(b) = 29 - 8 \\ n(b) = 21..... \\ hope \: it \: helps....

Answered by atulkumar8180
2

Step-by-step explanation:

n(A)=15

n(AUB)=29

n(ANB)=7

n(A)=15

n=15/A

n(AUB)=29

15/A×AUB=29

15AUB/A=29

15UB=29

B=29/15U

n(ANB)=7

15A(ANB)=7

15A×ANB=7

A×A=7/15NB

NB=7/15

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