If n(A) = 16 , n(B) = 18 , n(A intersection B) = 9 , find n(A U B )?
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your answer is n(a union b) is 34.
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Step-by-step explanation:
n(A∪B)=n(A)+n(B)−n(A∩B) −−−−−−− (1)
Given n(A)=16
n(B)=18
n(A∩B)=9
Putting values in equation 1
n(A∪B)=n(A)+n(B)−n(A∩B)
⇒n(A∪B)=16+18-9
⇒n(A∪B)=34-9
⇒n(A∪B)=25
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