Math, asked by ppdharshini2004, 6 months ago

If n(A)=2 and n(B)=3 then n(AXB)=6 ,then the total number of the relations in the set AXB​

Answers

Answered by aavalmariyam
4

Step-by-step explanation:

n(AXB) = n(A) x n(B)

=2 x 3

= 6

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