if n(A)=20 & n(B)=16then find n (AUB)= 30, find (AnB)
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Answered by
0
Answer:
Step-by-step explanation:
Answer:
n(A∪B)=n(A)+n(B)−n(A∩B)
:36=20+28-n(A∩B)
:36=48-(A∩B)
:A∩B)=48-36=12
Answered by
1
Step-by-step explanation:
n(AUB) =n(A) +n(B) - n(AnB)
30 = 20 +16 - n(AnB)
30= 36 - n(AnB)
n(AnB) =36-30
n(AnB)=6
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