If n(A)=20 , n(B)=28 and n(AUB)=36 then n(AΠB)=?
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Step-by-step explanation:
GIVEN:
If n (A) = 20, n (B) = 28 and n(AUB) = 36 then n(ANB)
TO FIND :
The value of n(ANB)
SOLUTION:
Given that n (A) = 20, n (B) = 28 and n(AUB) = 36
The formula in Set theory is given by :
n(AUB) = n(A) + n(B) - n(ANB)
Now substituting the values in the above formula we get,
3620+28 - n(AB)
3648 - n(ANB) - n(ANB)
= 48 - 36 = 12 n(ANB) = 12
.. the value of n(AB) is 12
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