Question

if n (A) =20, n(B)=28and n(AUB)=36then find n(A intersection B)​

Answer 1

Answer:

12

Step-by-step explanation:

n(a) + n(b) - n(anb) = n(aub)

Answer 2

n(A) + n(B) -n(A union B) = n(A intersection B)

Therefore, 20+28-36=48-36

= 12

So,the answer is 12

But I am not sure about the answer