if n(A)=20, n(B)=30,n(A interset B)=10, find n(A' interset B')
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we know that n (A union B)=n (A)
+n (B)-n (A intersect B)
=20+30-10
=50-10
=40
So n (A union B) is 40
+n (B)-n (A intersect B)
=20+30-10
=50-10
=40
So n (A union B) is 40
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