if n(A)=20,n(B)=30,n(A interset B)=10,find n(A union B)
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Answered by
1
n ( A union B) = n (A) + n ( B)
= 20+30
=50
= 20+30
=50
Answered by
0
we know that n (A union B) = n ( A) +n( B) -n (A intersect B)
》 》 =20 +30 -10
=50-10
=40
so n ( A union B) is 40
》 》 =20 +30 -10
=50-10
=40
so n ( A union B) is 40
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