If n(a)=20,n(b)=50,n(a union b)=60and n(b')=20,find n(a intersection b)and n(union)
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Explanation:
n(A)=20,n(B)=50,n(A∪B)=60 and n(B′)=20
We know that
n(A∩B)=n(A)+n(B)−n(A∪B)
n(A∩B)=20+50–60=10
Also n(B′)=n(U)−n(B)
So 20=n(U)−50
n(U)=50+20=70
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