if n (a) = 20 , n (b) =50 , n (aub) = 60 and n (b') = 20 , find n (anb)and n (u)
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Step-by-step explanation:
if n(a)=20n(b)=50,n(aub)=60 and n (b')=20.find n(anb) and n(u)
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Given:
n(a) = 20
n(b) = 50
n(a∪b) = 60 and n(b') = 20
To Find:
n(a∩b) and n(u)
Solution:
We know that,
n(a∪b) = n(a) + n(b) - n(a∩b)
So, rearranging the above equation, we get
n(a∩b) = n(a) + n(b) - n(a∪b)
By sustituting values, we get
n(a∩b) = 20 + 50 - 60 = 70 - 60 = 10
Also,
n(u) = n(b) + n(b') = 50 + 20 = 70
Hence, n(a∩b) is 10 and n(u) is 70.
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