Question

If n(A)=25, n(B)=40, n(AᴜB)=50 and n(B´)=25 find n(A∩B)​

Answer 1

Answer:

Step-by-step explanation:

Here's the answer!

Given : n(A) = 25; n(B) = 40 ; n (AU

B) = 50; n (B¹) = 25

Formula to be used: n (AUB) = n(A) + n (B)-n (ANB)

Substituting the given values in the above formula we get,

=> 50 = 25 + 40-n (ANB)

=> n(ANB) = 25+ 40 - 50

=> n(ANB) = 65-50 = 15

Hence n (ANB) = 15

We also know that,

n (B¹) = n(U) - n (B) Substituting the values we get,

25=n(U)- 40

=n(U)= 40+ 25 = 65.

Hence the universal set n (U) contains 65 elements.

Hope it helped !