If n(A)=25,n(B)=40,n(AUB)=50 and n(B') =25, find n(AnB)andn(U)
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Answer:
Step-by-step explanation:
n(A U B) = n(A) + n(B) - n(A ∩ B)
50 = 25 + 40 - n(A ∩ B)
50 - 65= - n(A ∩ B)
-15 = - n(A ∩ B)
n(A ∩ B) = 15
and , n(A)' = 25 -15 =10
n(U) = n(AUB) + n(AUB)'
n(U) =50 + {n(A)'+n(B') - n(A ∩ B)' }
n(U) = 50 + 35 - n(A ∩ B)'
n(U) = 85 - n(A ∩ B)'
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