Question

if n(A) =3 and n(B) = 2 then how many functions are there from A to B​

Answer 1

given ,

n(A) = 3 and n(B) = 2

then number of elements from A to B are n(A) * n(B) = 3*2 = 6

Now , number of functions from A to B are 2 power 6

Hence , the answer is 64.

Hope it helps you ...

Answer 2

Required number of relations are 64.

Given:

n(A) =3

n(B) = 2

To Find:

How many relations are there from A to B​

Solution:

n(A) = 3

n(B) = 2

Number of relations from A to B = $2^{n(A).n(B)}$

where n(A) is number of elements in A and n(B) is number of elements in B

Thus, n(A)*n(B) = 3*2 = 6

Therefore, required number of relations =  $2^{6}$  = 64.

#SPJ2