If n(A) = 3, n(B) = 4, n(A N B) = 2, then total number of relations from A to B is
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2
Step-by-step explanation:
n(A)=3, n(B)=4.
n(AnB)=2
then n(AUB)=5
using the formula
n(A)+n(B)=n(AUB)+n(AnB)
Answered by
0
n(a to b) = n(a)+n(b)_n(a and b)
= 3+4_2=5
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