if n(A)=3, n(B)=4 then find f+g
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Number of relations from A to B =2^(x*y)
where x is number of elements in A and y is number of elements in B
Here, x= n(A)= 3 and y= n(B)= 4
thus, x*y=3*4=12
Therefore, required number of relations= 2^(12)= 4096
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