Question

If n(A)=30, n(B)=45, n(AUB)=65, find i)n(AnB) ii)n(A-B) iii)n(B-A)



10,20,30

10,15,10

20,10,15

10,20,35


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Answer 1

Answer is given in the question.

And don't forget to solve my question.

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

If n(A) = 30 , n(B) = 45, n(AUB) = 65

i) n( A ∩ B) ii) n(A-B) iii) n(B-A)

• 10,20,30

• 10,15,10

• 20,10,15

• 10,20,35

EVALUATION

Here it is given that

n(A) = 30 , n(B) = 45, n(AUB) = 65

Now

n( A ∪ B) = n(A) + n(B) - n( A ∩ B)

⇒ 65 = 30 + 45 - n( A ∩ B)

⇒ n( A ∩ B) = 75 - 65

⇒ n( A ∩ B) = 10

i) n( A ∩ B) = 10

ii) n(A-B) = n(A) - n( A ∩ B) = 30 - 10 = 20

iii) n(B-A) = n(B) - n( A ∩ B) = 45 - 10 = 35

FINAL ANSWER

Hence the correct option is 10 , 20 , 35

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