Math, asked by anandjai5253, 9 months ago


if n(A) = 36, n (B) = 10 ,n[AUB]=40, find
n(AnB).
a 6
b) 3
2 10
d) 15​

Answers

Answered by rahul456841
4

Answer:

6

Step-by-step explanation:

n(AUB) = n(A) + n(B) - n(Anb)

40 = 36+10-n(Anb)

n(Anb) = 46-40 = 6

Answered by qwsuccess
0

n(A∩B)=6

Given:

n(A)=36

n(B)=10

n(A∪B)=40

To Find:

n(A∩B)=?

Solution:

n(A) means number of elements in set A.

n(B)= number of elements in set B

n(A∪B)= Number of elements in A union B

n(A∩B)= Number of elements in A intersection B

Using Formula

n(A∪B)= n(A)+n(B)-n(A∩B)

40=36+10-n(A∩B)

40=46-n(A∩B)

n(A∩B)=46-40=6

#SPJ3

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