if n(A) = 36, n (B) = 10 ,n[AUB]=40, find
n(AnB).
a 6
b) 3
2 10
d) 15
Answers
Answered by
4
Answer:
6
Step-by-step explanation:
n(AUB) = n(A) + n(B) - n(Anb)
40 = 36+10-n(Anb)
n(Anb) = 46-40 = 6
Answered by
0
n(A∩B)=6
Given:
n(A)=36
n(B)=10
n(A∪B)=40
To Find:
n(A∩B)=?
Solution:
n(A) means number of elements in set A.
n(B)= number of elements in set B
n(A∪B)= Number of elements in A union B
n(A∩B)= Number of elements in A intersection B
Using Formula
n(A∪B)= n(A)+n(B)-n(A∩B)
40=36+10-n(A∩B)
40=46-n(A∩B)
n(A∩B)=46-40=6
#SPJ3
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