If n(A) = 3x n(B) = 2x n(A intersection B) = n(AUB)' = x find x and n (A-B)
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given n(A) = 3 x
given n(B) = 2 x
given n(A ∧ B) = n( A U B)' = x
n(A - B) = n(A) - n (A ∧ B) = 3x - x = 2 x
I am also doing other answers in case u want.
n(B - A) = n(B) - n(A ∧ B) = 2x - x = x
n (A U B) = n(A) + n(B) - n (A ∧ B) = 3x + 2x - x = 4 x
U = total universal set = A U B U (AUB)'
n(U) = n(A U B) + n (A U B)' = 4 x + x = 5 x
given n(B) = 2 x
given n(A ∧ B) = n( A U B)' = x
n(A - B) = n(A) - n (A ∧ B) = 3x - x = 2 x
I am also doing other answers in case u want.
n(B - A) = n(B) - n(A ∧ B) = 2x - x = x
n (A U B) = n(A) + n(B) - n (A ∧ B) = 3x + 2x - x = 4 x
U = total universal set = A U B U (AUB)'
n(U) = n(A U B) + n (A U B)' = 4 x + x = 5 x
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