If n(a)=4,n(b)=5,n(u)=7 and n(a intersection b)=2 then find the value of n(a union b )'
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Step-by-step explanation:
we have a formulae that
n(AUB)=n(A)+n(B)-n(AintersectionB)
n(AUB)=4+5-2
n(AUB)= 7
hope it helps you friend
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